November 2025 Contest — Grade 3
The November 2025 North Star contest paper for Grade 3 has 12 questions and a 45-minute limit. Two sample questions with worked solutions are below, and you can take the whole paper online for free — no account, no sign-up.
- Grade
- Grade 3
- Questions
- 12
- Time limit
- 45 minutes
- Contest
- November 2025
- Subject
- Mathematics
- School year
- 2025-26
Before you start
- The timer starts when you press Start and runs for 45 minutes.
- Answer the 12 questions in any order; each is multiple choice.
- Your answers are marked as you go. Nothing is saved to an account, so finish in one sitting.
Sample questions
The first and last questions from this paper, with their worked solutions.
Question 1 — Logical Reasoning & Problem Solving
The final game in the North Star soccer tournament is on Monday. The game before it (the semifinal) happened three days before Monday. What day was that semifinal game?
- A.Thursday
- B.Saturday
- C.Sunday
- D.Tuesday
- E.Friday
Show the worked solution
To find the day of the semifinal game, we need to count backward three days from Monday.
1 day before Monday is Sunday.
2 days before Monday is Saturday.
3 days before Monday is Friday.
So, the semifinal game was on Friday.
Question 12 — Logical Reasoning & Problem Solving
Lexie has a farm with goats and chickens. Every goat has 4 legs, and every chicken has 2 legs. Lexie knows she always has more chickens than goats. One Monday, she counted a total of 62 legs on the farm. What is the largest number of goats that Lexie could have that day?
- A.8
- B.9
- C.10
- D.11
- E.12
Show the worked solution
To find the largest number of goats Lexie could have, we can test the options starting from the largest number of goats to see which one fits all the rules.
Let's remember the rules:
Every goat has 4 legs.
Every chicken has 2 legs.
There must be more chickens than goats.
The total number of legs is 62.
Let's test the options:
1. Let's try 12 goats (Option E):
12 goats would have: 12 + 12 + 12 + 12 = 48 legs.
The remaining legs for the chickens would be: 62 - 48 = 14 legs.
Since each chicken has 2 legs, the number of chickens would be: 14 divided by 2 = 7 chickens.
But Lexie must have more chickens than goats. Here, 7 chickens is less than 12 goats, so this does not work.
2. Let's try 11 goats (Option D):
11 goats would have: 11 + 11 + 11 + 11 = 44 legs.
The remaining legs for the chickens would be: 62 - 44 = 18 legs.
The number of chickens would be: 18 divided by 2 = 9 chickens.
Here, 9 chickens is less than 11 goats, so this does not work.
3. Let's try 10 goats (Option C):
10 goats would have: 10 + 10 + 10 + 10 = 40 legs.
The remaining legs for the chickens would be: 62 - 40 = 22 legs.
The number of chickens would be: 22 divided by 2 = 11 chickens.
Here, 11 chickens is more than 10 goats. This fits all the rules perfectly!
Therefore, the largest number of goats Lexie could have is 10.
The answer is C
Take the whole paper
All 12 questions, 45 minutes, marked as you go. No account needed.